The height of a swing above ground can be modelled by equation : h=1.5+sin 3t when is the swing first 1m above the ground(to the nearest one tenth of a second)?

3 Answers

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jeew-m | College Teacher | (Level 1) Educator Emeritus

Posted on

The height can be modelled by the following equation.

h=1.5+sin 3t

When the swing is 1m above ground h = 1m
`1 = 1.5+sin3t`

`-0.5 = sin3t`

`-sin(pi/6) = sin3t`

We know that

`sin(pi+theta) = -sintheta `

Let us say;

`sin(pi+pi/6) = sin3t`

`3t = (7pi/6)`

`t = (7pi)/18`

`t = 1^0 13^0 18''`


Answer to the nearest tenth second;

`t = 1^0 13^0 20''`



The calculations are considered as motion starting by increment angle.




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oldnick | (Level 1) Valedictorian

Posted on

Note that the funcytion has the same period T of function y= sin 3t

Indeed: if `3/2+sin3t_1=3/2+sin3t_2 rArr sin 3t_1= sin3t_2` 

that is:  `t_2= pi-t_1`  I one round  of circle.

Then :



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oldnick | (Level 1) Valedictorian

Posted on

To know when the swiing is at 1 mt from the ground you have to solve eaquation :


That means:      `sin 3t= 1-3/2=-1/2`

This causes:      `3t= 11/6 pi+2kpi`     `t=11/18 pi +2/3 kpi`

and:                  `3t=7/6 pi+2kpi`      `t=7/18 pi +2/3 kpi`


So solution are    `t_1=1/18 pi (11+12k)`  `t_2=1/18 pi (7+12k)`


Let you see, red line is function  y= 3/2+ sin3t, while  blue line is function y=1

The point you are searching for are the point wich red line intercept blue one.