1 Answer | Add Yours
The heat of fusion of water is 80.9 calories per gram. To melt each gram of ice to liquid water 80.9 calories are required.
To melt 45 g of ice at 0 degree C, the number of calories required is given by 45*80.9 = 3640.5.
The required heat to melt 45 g of ice is 3640.5 calories.
We’ve answered 318,989 questions. We can answer yours, too.Ask a question