# I have a robot with two arms. The first with a mass of 69kg and it moves at a speed of 4m/s. The second arm is mounted on the first arm and has a mass of 7kg and moves at a speed of 2.2m/s. The...

I have a robot with two arms. The first with a mass of 69kg and it moves at a speed of 4m/s.

The second arm is mounted on the first arm and has a mass of 7kg and moves at a speed of 2.2m/s.

The second arm strikes an enclosure door. What is the kinetic energy of the entire robot system?

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### 1 Answer

The first with a mass of 69kg and it moves at a speed of 4m/s.

The second arm is mounted on the first arm and has a mass of 7kg and moves at a speed of 2.2m/s.

We know

`KE=(1/2)mv^2 J`

Thus KE of one arm is

`KE_1=(1/2)xx69xx16`

`=552` J

KE of the second arm

`KE_2=(1/2)xx7xx(2.2)^2`

`=16.94` J

Thus total KE ,

`KE=KE_1+KE_2`

`=552+16.94`

`=568.94` J