I have a problem to calculate this kind of quadratic equation 5sinsquarex+sin2x-3=0. I know that if we have only sinx as the second part of this equation, it'll be easy to find roots: it would be sinx= (-b+squarerootof bsquare-4ac)all over 2a. but How can I find sin2x? thank you very much
We can write this equation as
So equation can be written as
squaring both side
Substitute the values of x in original equation to find the value of x.It may possible all value of above x not satisfy the give equation.
Once you have x the you can calculate sin(2x).