The half-life of iodine-131 is 8.03 days. What percentage of an iodine-131 sample will remain after 38.5 days?

1 Answer | Add Yours

gsenviro's profile pic

gsenviro | College Teacher | (Level 1) Educator Emeritus

Posted on

Half life represents the time period after which a substance will lose half of its original content. Thus, in the given example, half of the starting amount  of iodine-131 will be left after 8.03 days. In another 8.03 days (that is, after 16.06 days from start), another 50% will be lost. We will, effectively, be left with only 25% of the original content. 

In 38 days, 38/8.03 = 4.79 half lives would have been gone. 

The amount of a material left, after a certain number of half lives can be calculated as:

Nt/N0 = 1/{(2)^(t/t1/2)}

where, t1/2 is half live and t/t1/2 is the number of half lives elapsed.

Thus, the fraction iodine-131 left after 4.79 half lives is:

Nt/N0 = 1/(2^4.79) = 0.036.

Thus, only 0.036 or 3.6% fraction of iodine-131 would be left after 38.5 days.

Hope this helps.

We’ve answered 318,988 questions. We can answer yours, too.

Ask a question