Half life for Carbon-14 is 5,730 years.  If yous tart out with 50 grams, how long will it take until it reaches 2 grams? Use A = P(1/2)^t/5730 Find t correct to the nearest whole year.

Expert Answers
lemjay eNotes educator| Certified Educator


To solve for the number of years it takes to the carbon to decay from 50g to 2g, plug-in A=2 and P=50 to the given formula.


Then, divide both sides by 50 to have (1/2)^(t/5730) at the right side of the equation.



To remove the t in the exponent, apply the loagrithm property ln `a^m = mlna` . So, take the natural logarithm of both sides of the equation.



Then, isolate t. To do so, multiply both sides by 5730.

`5730*ln(1/25) = t/5730 ln(1/2) * 5730`


And, divide both sides by ln(1/2).




Rounding off to nearest whole number, it becomes:


Hence, it takes 22,609 years for the Carbon-14 to decay from 50g to 2g.

steveschoen eNotes educator| Certified Educator

Hi, Kristin.

First, we sub in 50 for P and 2 for A.  Then, we solve for t.

First, divide each side by 50.  So:

2/50 = (1/2)^t/5730

Then, take the log (base 10) of each side:

log(2/50) = log((1/2)^t/5730)

With this, though, the exponent on the right comes down in front of the log, as a factor, a multiplier.  So, we have:

log(2/50) = (t/5730)*log(1/2)

Then, we can divide each side by log(1/2)"

[log(2/50)]/[log(1/2)] = t/5730

The right side is 4.644.  Then, multiply each side by 5730, giving t = 26,610.12.  So, it would take 26,610.12 years to get 2 grams.

I hope this helps, Kristen.  Good luck.

Till then,


justaguide eNotes educator| Certified Educator

The half life of carbon 14 is 5730 years. If the starting amount of C-14 is P, the amount after t years is given by `A = P*(1/2)^(t/5730)`

Let the time taken for 50 g to decay to 2 g be t:

2 = `50*(1/2)^(t/5730)`

=> `log(1/25) = (t/5730)*log(1/2)`

=> `t = 5730*(log(1/25))/(log(1/2))`

=> t `~~` 26609 years

The time in which 50 g of C-14 decays to 2 g is approximately 26609 years.