`h(x) = sec(x^2)` Find the derivative of the function.

1 Answer

sciencesolve's profile pic

sciencesolve | Teacher | (Level 3) Educator Emeritus

Posted on

You need to use the chain rule to evaluate the derivative of the function, such that:

`h'(x) = (sec(x)^2)'*((x)^2)'`

`h'(x) = 2x(sec(x)^2)*(tan (x)^2)`

`h'(x) = 2x(sec(x)^2)*(tan (x)^2)`

Hence, evaluating the derivative of the function, using the product rule, yields `h'(x) = 2x(sec(x)^2)*(tan (x)^2)` .