`h(x) = sec(x^2)` Find the derivative of the function.

Textbook Question

Chapter 2, 2.4 - Problem 46 - Calculus of a Single Variable (10th Edition, Ron Larson).
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sciencesolve | Teacher | (Level 3) Educator Emeritus

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You need to use the chain rule to evaluate the derivative of the function, such that:

`h'(x) = (sec(x)^2)'*((x)^2)'`

`h'(x) = 2x(sec(x)^2)*(tan (x)^2)`

`h'(x) = 2x(sec(x)^2)*(tan (x)^2)`

Hence, evaluating the derivative of the function, using the product rule, yields `h'(x) = 2x(sec(x)^2)*(tan (x)^2)` .

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