`h(t) = t/(t + 3), [-1,6]` Find the absolute extrema of the function on the closed interval.

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Chapter 3, 3.1 - Problem 28 - Calculus of a Single Variable (10th Edition, Ron Larson).
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mathace | (Level 3) Assistant Educator

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Given: `h(t)=t/(t+3),[-1,6]`

Find the critical values for t by setting the derivative equal to zero and solving for the t value(s).




A critical value will not exists for this function.

Plug in the critical t value(s) and the endpoints of the closed interval into the h(t) function.




Examine the h(t) values to determine the absolute extrema.

The absolute maximum is the point `(6,2/3).`

The absolute minimum is the point `(-1,-1/2)`


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