`h(t) = t^2 + 4t, (1, 5)` Find the slope of the tangent line to the graph of the function at the given point.
hkj1385 | Certified Educator
The given function is:-
h(t) = (t^2) + 4t
differentiating both sides w.r.t 't' we get
h'(t) = 2t + 4
Now, slope of the tangent at the point (1,5) = h'(1) = 2*1 + 4 = 6