`h(t) = t^2 + 4t, (1, 5)` Find the slope of the tangent line to the graph of the function at the given point.

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Chapter 2, 2.1 - Problem 10 - Calculus of a Single Variable (10th Edition, Ron Larson).
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hkj1385 | (Level 1) Assistant Educator

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The given function is:-

h(t) = (t^2) + 4t

differentiating both sides w.r.t 't' we get

h'(t) = 2t + 4

Now, slope of the tangent at the point (1,5) = h'(1) = 2*1 + 4 = 6

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