`h(s) = (s^3 - 2)^2` Find the derivative of the algebraic function.

Expert Answers
hkj1385 eNotes educator| Certified Educator

Note:- If y = x^n ; where n = constant ; then dy/dx = n*x^(n-1)

Now,

`h(s) = (s^3 - 2)^2`

`h'(s) = (2)(3s^2)*(s^3-2)^1`

`or, h'(s) = (6s^2)*(s^3 - 2)`

`or, h'(s) = 6s^5 - 12s^2`

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