We can write the equation of the reactions to be:

BaCl2 + Na2SO4 ---> BaSO4 + 2NaCl

The mass of the unknown soluble sulphate should be given in order to solve for the volume of the BaCl2 solution. The procedure for the determination of the volume of BaCl2 solution is as follows:

1. From the mass of the Na2SO4, we can solve for the moles Na2SO4 using the molar mass of Na2SO4.

2. From the balanced equation, we can see that the ration of Na2SO4 and BaCl2 is 1:1 therefore: moles Na2SO4 = moles BaCl2

3. Next, we convert the moles of BaCl2 to mass BaCl2 using the molar mass of BaCl2. The mass of BaCl2 calculated is the weight of BaCl2 in the solution. Meaning it is the 10%wt of the unknown volume.

4. From the mass of the BaCl2, we can now solve for the volume of the solution.

Wt% = mass BaCl2/mL solution

**mL solution = (10/100) x ( mass BaCl2)**

**please provide the value of the mass of the Na2SO4 to solve the problem.

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