What are the characteristics of the parabola: f(x) = x^2 – 8x + 7?
The equation of the parabola given is : f(x) = x^2 – 8x + 7
f(x) = x^2 – 8x + 7
=> x^2 - 8x + 16 + 9
=> (x - 4)^2 - 9
The standard form of the parabola y = a*(x - h)^2 + k can be used to determine all its characteristics.
Here, a is positive, indicating that the parabola opens upwards.
The vertex is at (h, k). For the equation given it is (4, -9)
The the axis of symmetry is x = 4
The graph does not intersect the x-axis.
The y-intercept of the parabola is (0, 7).
The x-intercepts can be determined by equating (x - 4)^2 - 9 = 0 and solving for x.
This gives (1, 0) and (7, 0)
The domain of the parabola is all the values that x can take for real values of y. Here it is R.
The range of the parabola is all the values y can take for x lying in the domain. Here it is [-9 , inf.]