# Find the x-intercept and the y-intercept of 1/2x -2y=4. Graph the function y=-2x+6 with the domain-1<x<5 What's the range of function above? ...

Find the x-intercept and the y-intercept of 1/2x -2y=4.

Graph the function y=-2x+6 with the domain-1<x<5

What's the range of function above?

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You will note that I have adjusted your question as eNotes rules do not allow for multiple questions to be answered. Please repost your other question or refer to the links provided below to help you. In fact, if you find the x and y intercepts the same way in both equations you will be able to graph your equation anyway.

`1/2x - 2y = 4`

The x and y intercepts mean that ( at those points) x = 0 on the y-intercept and y=0 on the x intercept. Because these are intercepts that particular fact never changes.

So, to find x and y on the x-intercept whrere we know that y=0 we use substitution:

`1/2x - 2(0) = 4` because we know y=0

`therefore 1/2x=4`

`therefore x=4 times 2 = 8`

x-intercept: (x;y) : (8;0)

Now on the y intercept:

`1/2(0)-2y = 4`

Note how we have gone back to the same equation and this time, because we know x=0 on the y intercept we substitute the x value of 0

`therefore -2y=4`

`therefore y=4/-2`

`therefore y=-2`

y-intercept:(x;y):(0;-2)

You can graph an equation with this information. Plot the points on your graph. The width of your graph (the horizontal x-axis will start at -1 and end at 5)

**Ans: x intercept:(8; 0) y intercept: (0; -2)**

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