Glucose is produced in plants through the process of photosynthesis, according to the following BALANCED equation. 6 CO2 (g) + 6 H20 (l) = C6H12O6 (aq) + 6 O2 (g) how many moles of oxygen gas will...

Glucose is produced in plants through the process of photosynthesis, according to the following BALANCED equation.

6 CO2 (g) + 6 H20 (l) = C6H12O6 (aq) + 6 O2 (g)

how many moles of oxygen gas will be produced if 4.0 moles of glucose are produced?

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Asked on by wildboy839

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gsenviro's profile pic

gsenviro | College Teacher | (Level 1) Educator Emeritus

Posted on

Using the given balanced chemical equation for production of glucose

6 CO2(g) + 6H2) (l) --> C6H12O6 (aq) + 6O2 (g)

Using stoichiometry

1 mole of glucose (C6H12O6) is produced along with 6 moles of oxygen (O2)

Therefore, 4 moles of glucose will be produced along with 6x4/1  moles of Oxygen or 24 moles of oxygen.

Ans: 24 moles of oxygen

aishukul's profile pic

aishukul | Student, Grade 10 | (Level 3) Honors

Posted on

`4 mol C6H12O6*(180g C6H12O6) / (1 mol C6H12O6)* (1 mol O2)/(32 g O2)=`

C6H12O6 is glucose. 

Since 1 mol of any element equals the molar mass of that element, in this case, we can find the atomic masses of Carbon, Hydrogen, and Oxygen, multiply them by the number of atoms each has, then add the totals together to get molar mass of glucose:

Carbon's atomic mass is 12. Since there are 6 atoms (C6), we multiply 6 times 12 to get 72. Oxygen's is 16 so we multiply 6 times 16 to get 96. Hydrogen's is 1 so multiply 1 times 12 since there are 12 atoms of Hydrogen (H12) to get 12. Now we can add the totals together: 72+96+12=180. 180 is the molar mass. As shown in the equation above, you make a proportion showing that the molar mass of glucose (180) equals 1 mol of glucose. From this, we can cancel out the mole units from the 4 mol and the 1 mol. Then multiply the proportion times the proportion of 1 mol O2 over the molar mass of O2. Likewise, to find molar mass, you take atomic mass of Oxygen, multiply by number of atoms (2) to get 32. This is how we get the proportion of mol/molar mass.

Now we can cancel out the gram units from the 180 g glucose and the 32 g O2, leaving us with only the mol unit from the O2 so we know the final answer will be in moles of O2, which is oxygen gas.

Finally, we can multiply 4 times 180 then divide by 32 to get answer.

`4*180=`

`720`

`720 / 32`

`22.5 `

The answer is 22.5 moles of O2 (oxygen gas).

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