Glencoe Science (level blue) chapter 17 test practice:
Describe the reaction using the names. Discuss which bonds are broken and how atoms are rearranged to form new bonds.
I'm so frustrated.
The equation provided in the problem is incorrect. The chemical formula of calcium carbonate is `CaCO_3` , not `CaCO_2` . `SiO_3` also does not exist in isolation and is a negatively charged cation that can only exist with a positive anion.
The correct equation is: `CaCO_3+SiO_2=CaSiO_3+CO_2` . This is a single displacement reaction.
`CaCO_3` is the chemical formula for calcium carbonate. The anion in this compound is `Ca^(2+)` and the cation is `CO3^(2-)` . `SiO_2` is silicon dioxide.
In the reaction as `SiO_2` reacts with `CaCO_3` , in the compound `CaCO_3` , the `CO_2` is replaced by `SiO_2` . The `CaCO_3` molecule is broken to form `CaO + CO_2` . Then the `CaO` combines with `SiO_2` to form `CaSiO_3` .
As a result CO_2 is set free.
CaCO2+SiO3=CaSiO3+CO2 is a single replacement reaction. If you look closer into the problem you can see that the cation (negatively charges part aka `CO3^-` and `SiO2^-` ) switch places to replace each other. The CO2 seperated and the SiO3 formed a bond with the anion (positively charged) Ca