We have the function f(x) = (x^2 - 2^2)/(x - 2). For x = 2, it is seen that f(x) takes the form (2^2 - 2^2)/(2 - 2) = 0/0 which is indeterminate.

To find the value of f(x) for x = 2, we have to use limits.

`lim_(x->2)((x^2 - 2^2)/(x - 2))` = `lim_(x->2)(((x-2)(x+2))/(x-2))` = `lim_(x->2)(x + 2)` = 4

The value of f(2) is not defined as such but as x tends to 2, f(2) tends to 4. Using limits, we can take the value of x as close to 2 as we want, and in this way it is determined that f(2) is equal to 4.

**The value of (x^2 - 2^2)/(x - 2) for x = 2 is equal to 4.**

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now