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The position vectors of A is 4i+7j.
The position vector of the point C is 10i+10j.
We want the position vector of a point P which divides the vector AB in the ratio 3:2.
We know that the position vector of a point Qthat divides the position vector P(x1i+y1j) and R(x2i+y2j) in m: n ratio is (nx1+mx2)i/(m+n)+(ny1+my2)j/(m+n).
So the position vector of B that divides the position vectors A(4i+7j) and C(10i+10j) is B =(2*4+3*10)i/(3+2)+(2*7+3*10)j/(3+2)}.
So B = (38/5)i+(54/5)j = 7.6i+10.8j.
Therefore the position vector of B is 7.6i+10.8j which divides the position vector of A and C in the ratio 3:2.
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