Given that x,y>0 find x/y if x+6y>0 2 (lgx - lgy) = lg (x+ 6y) -lg y

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Given that x> 0 and y >0.

Also, given that x+ 6y > 0

We need to find x/y.

2 (lgx - lgy) = lg (x+ 6y) -lg y.

We know from logarithm properties that log(a) - log(b) = log (a/b)

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