Given the sum of two numbers = 3 and the product = 2 find the sum of the squares of the numbers.
Let the two numbers we have to find the squares of be A and B.
Now their sum is A + B = 3
Their product is A*B = 2
We need A^2 + B^2.
This can be written as (A + B)^2 - 2A*B
=> 3^2 - 2*2
=> 9 - 4
Therefore the required sum of the squares is 5.
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