Given sinx=1/4 and cosx=3/4 what is sec2x ?

Expert Answers

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We are given that sin x = 1/4 and cos x = 3/4. We have to find sec 2x.

sec 2x = 1/ cos 2x

cos 2x = (cos x)^2 - (sin x)^2

=> (3/4)^2 - (1/4)^2

=> (9 - 1)/ 16

=> 8/ 16

=> 1/2

So sec 2x = 2

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