Given the sequence 3,9,27,...determine the nth term of the sequence and the 11th term .

Expert Answers

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3, 9, 27, .....

We notice that what we have is a geometric progression where r= 3.

a1= 3

a2= 3*3 = 9

a3= 3*3^2 = 27

Then:

an = a1*3^(n-1)

......

a11= 3*3^10 = 3^11 = 177147.

an = 3*3^(n-1) = 3^n

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