We have a right triangle with A = 90 degrees and we have to calculate cos B / sin C + cos C / sin B
Let's take the sides opposite angle A as a, that opposite angle B as b and that opposite angle C as c.
cos B...
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We have a right triangle with A = 90 degrees and we have to calculate cos B / sin C + cos C / sin B
Let's take the sides opposite angle A as a, that opposite angle B as b and that opposite angle C as c.
cos B / sin C + cos C / sin B
=> [(c / a)/(c/ a)] + [(b/a)/(b/a)]
=> 1 + 1
=> 2
The expression = 2.