We have a right triangle with A = 90 degrees and we have to calculate cos B / sin C + cos C / sin B

Let's take the sides opposite angle A as a, that opposite angle B as b and that opposite angle C as c.

cos B...

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We have a right triangle with A = 90 degrees and we have to calculate cos B / sin C + cos C / sin B

Let's take the sides opposite angle A as a, that opposite angle B as b and that opposite angle C as c.

cos B / sin C + cos C / sin B

=> [(c / a)/(c/ a)] + [(b/a)/(b/a)]

=> 1 + 1

=> 2

**The expression = 2.**