Given a muriatic acid with a concentration of 11.7 M, how many mL of the muriatic acid solution in 9.55g of hydrochloric acid. Show complete step by step solution to explain the process and answer.

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sanjeetmanna | College Teacher | (Level 3) Assistant Educator

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Given 

Molarity of HCl (M) = 11.7 M

Volume of HCl (V) = ? ml

Mass of HCl (m) = 9.55 g

Molar mass of HCl = 36.46 `(g)/(mol)`

Method 1

Formula

`Molarity = ((mass)/(molar mass))*(1000/V)`

`11.7 = (9.55/36.46)*(1000/V)`

`V = (9.55*1000)/(11.7*36.46)`

`V = 9550/426.528`

V = 22.39 ml

Method 2

Molarity = moles / volume in litres

Moles = mass/molar mass

Moles = `9.55/36.46`

Moles = 0.2619

11.7 = 0.2619/Volume

Volume = `0.2619/11.7`

Volume = 0.02238 litres = 22.38 ml.

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