Given a muriatic acid with a concentration of 11.7 M, how many mL of the muriatic acid solution in 9.55g of hydrochloric acid. Show complete step by step solution to explain the process and answer.

Expert Answers
sanjeetmanna eNotes educator| Certified Educator

Given 

Molarity of HCl (M) = 11.7 M

Volume of HCl (V) = ? ml

Mass of HCl (m) = 9.55 g

Molar mass of HCl = 36.46 `(g)/(mol)`

Method 1

Formula

`Molarity = ((mass)/(molar mass))*(1000/V)`

`11.7 = (9.55/36.46)*(1000/V)`

`V = (9.55*1000)/(11.7*36.46)`

`V = 9550/426.528`

V = 22.39 ml

Method 2

Molarity = moles / volume in litres

Moles = mass/molar mass

Moles = `9.55/36.46`

Moles = 0.2619

11.7 = 0.2619/Volume

Volume = `0.2619/11.7`

Volume = 0.02238 litres = 22.38 ml.