Given h(x)=2/x+1 find h^-1 and find the domain and range
To find the inverse function we set it equal to y and solve for x.
Hence the inverse function is `h^(-1)(x)=[2-x]/x`
Domain: The new function is not defined for x=0, thus the domain is D=`(-oo,0)U(0,oo)`
Range: Since h(x) is not defined for x=-1, then -1 can't be an element of the range of `h^(-1)(x)`
The following graph of the inverse function confirm our findings.