Given the function y= 3 sin [2 (x- 30 degrees)] , find the smallest positive value for x that gives a maximum value for y.

Asked on by smbb1

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aruv | High School Teacher | (Level 2) Valedictorian

Posted on

`y=3 sin(2(x-30))`

for maximum value of y  we want derivative of y with respect to x.


for maximum









`(d^2y)/(dx^2)}_{x=75^o}=-12 <0`

Thus x=75 degree then y has aximum value.

Thus answer to question is x=75 degree.

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