# Given function f(x)=x2+4x-5 determine the vertex, axis of symmetry calculate y-intercept find additional point on graph graph function.  Submit graph. Need answer asap.

## Expert Answers First thing to notice is that we're dealing with a parabola, so we know it has a vertex, vertical axis of symmetry, etc.

Always factor if possible.`f(x) = x^2+4x-5=(x-1)(x+5)`

Start by finding the roots. If 0 = (x-1)(x+5), then x = 1 or -5.

Now hit up the y-intercept.  If x = 0, `f(0)=-5` .

The vertex is going to be right between the roots, so average them: `(1+(-5))/2)=-2`.  The axis of symmetry is x -2.

So the vertex is at x = -2, and y = `f(-2)=(-2)^2+4(-2)-5=4-8-5=-9` .  (-2, -9).

To find another point on the graph, you just choose a random x.  How about 3.  `f(3)=3^2+4*3-5=9+12-5=16` .  (3, 16)

Double-check this graph to make sure the work was correct...

Approved by eNotes Editorial Team

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

• 30,000+ book summaries
• 20% study tools discount
• Ad-free content
• PDF downloads
• 300,000+ answers
• 5-star customer support