# Given the following function(a)find the domain,(b)determine the vertical asymptote.(c) draw the graphy=log(4-x)

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Given `y=log(4-x)`, find the domain, the vertical asymptote and draw the graph.

Consider the function `y=logx` . This function is undefined for `x<=0` , has a vertical asymptote at x=0, and increases on its domain.

The given function reflects the basic log function across the y-axis. Then the given function takes the transformed function and translates it horizontally 4 units to the right. (Or you can translate the log function 4 units left, and then reflect across the y-axis).

Thus:

(1) **The domain is `x<4` **since the function is undefined for `x>=4` as the domain of the log function is positive. `4-x` is positive if `x<4`

(2) **There is a vertical asymptote at x=4.**

The graph of `y=logx` is in black; the graph of `y=log(-x)` is in red (the reflection over the y-axis); and the graph of `y=log(4-x)` is in blue.