Given f(x)=x+1; g(x)=√x-2; h(x)=2/x Perform the indicated operations and supply the domain and range of the resulting function: h^-1
To find the inverse function we write y=2/x and solve for x.
Hence the inverse function is `h^(-1)(x)=2/x`
The domain is D=`(-oo,0)U(0,oo)`
The function can never be equal zero, so R=`(-oo,0)U(0,oo)`
The following graph help explain why the function and its inverse are the same.