`f(x) = 2x^2 - 5` and `g(x) = 4-2x` substitute g(x) for every value of x in f(x)
`therefore` (f of g)x can be written as:
f(g(x))= `2(4-2x)^2 - 5`
= `2(16 - 16x + 4x^2) -5`
= `32- 32x +8x^2 -5`
= `8x^2 -32x + 27`
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