We have the equation x^2-3x+1=0

x^2 - 3x + 1 = 0

x1 = [-b + sqrt ( b^2 - 4ac)]/2a

=> [ 3 + sqrt(9 - 4)]/2

=> 3/2 + sqrt 5/2

x2 = 3/2 - sqrt 5/2

The sum of the square of these roots is:

(3/2 + sqrt 5/2)^2 + ( 3/2 - sqrt 5/2)^2

=> 2*(3/2)^2 + 2* 5/4

=> 2*9/4 + 5/2

=> 9/2 + 5/2

=> 14/2

=> 7

**The sum of the roots is 7 which is a natural number.**

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now