Given the equation `4x^2 + 3y^2 - 24y = 0`

By completing the square and rewriting in the general form, we can identify center as well as major axis.

Complete the square.

`4x^2 + 3y^2 - 24 y = 0`

`4(x^2) + 3(y^2 - 8y) = 0` Multiply each term by `1/4.`

`(x^2) + 3/4(y^2 - 8y) = 0` Multiply each term by `1/3`

`1/3(x^2) + 1/4(y^2 - 8y) = 0` Complete square for y.

`1/3(x^2) + 1/4(y^2 - 8y + 16) = 0 + (1/4)(16)` Factor.

`x^2/3 + (y - 4)^2/4 = 4` Multiply every term by `1/4` to get equation =1.

`x^2/12 + (y-4)^2/16 = 1`

From this, we can see that the center is (0, 4). This now shows us either choice "b" or "d" is correct. Since a>b, this makes 16 = a^2, therefore the major axis is vertical. Therefore this eliminates choice "d".

**The solution is choice "b".**