Given cot x=1/5, what is the value cos^2 x?
We have cot x= 1/5. We need the value of (cos x)^2
(sin x)^2 + (cos x)^2 = 1
divide all terms by (sin x)^2
=> 1 + (cot...
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cot x= 1/tan x
since 1/5= 1/tan x, tan x =5
In a right angled triangle, tan x= opposite side/ adjacent side = 5/1=5
so, hypo. side= square root 26
cos x = adjacent side / hypo. side= 1/ square root 26
therefore since cos 2x= 1- 2cos^2 x= 1- 2(1 / square root 26) ^2