Given the atm. of uniform density 1.5 Kg/m^3, explain how high a column of air can cause the barometer to read 80 cm of Hg?
You should start conditioning that the pressure of air needs to be equal to pressure of Hg such that:
`h_1*rho_1*g_1 = h_2*rho_2*g_2`
`h_1` represents the height of column of Hg
`h_2` represents the height of column of air
You need to convert the units of mesure of height of Hg in meters such that:
`80 cm = 0.8 m`
Substituting the given values in equation above yields:
`0.8 m*13530 (Kg)/(m^3) = h_2*1.5 (Kg)/(m^3) `
`h_2 = (0.8 m*13530 (Kg)/(m^3))/(1.5 (Kg)/(m^3))`
`h_2 = 7.2 Km`
Hence, evaluating the height of column of air,under the given conditions, yields `h_2 = 7.2 Km` .