Given 0=<x<2pi find the roots of the equation sinx=-1/2.

Expert Answers

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We have to find the values of x for which sin x = -1/2 in the range [0, 2*pi)

sin x = -1/2

=> x = arc sin (-1/2)

x = 210 degrees

x = 330 degrees

The values of x in the range [0, 2*pi) for which sin x = -1/2 are x = 210 degrees and x= 330 degrees.

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