Geometry A rectangle has a perimeter of 60 m and an area of 200 m2. Find the length x and width y, x > y, of the rectangle.

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The length of the rectangle is x and the width is y. The area of a rectangle is x*y and the perimeter is 2(x + y)

Here we have area = 200

=> xy = 200

Perimeter = 60

=> 2(x + y) = 60

=> x + y =...

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The length of the rectangle is x and the width is y. The area of a rectangle is x*y and the perimeter is 2(x + y)

Here we have area = 200

=> xy = 200

Perimeter = 60

=> 2(x + y) = 60

=> x + y = 30

=> x = 30 - y

Substitute in xy = 200

(30 - y)y = 200

=> y^2 - 30y + 200 = 0

=> y^2 - 20y - 10y + 200 = 0

=> y(y - 20) - 10(y - 20) = 0

=> (y - 20)(y - 10) = 0

y = 20 or y = 10

As y is the width y = 10 and the length  = 20.

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