Geometric Progression What is the value of x and y if 2, x, y, 16 form a geometric progression ?
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Consecutive terms of a GP have a common ratio. if 2, x, y, 16 form a GP.
=> 16/y = x/2
=> x =...
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The geometric mean theorem of a g.p. states:
x^2 = 2y (1)
y^2 = 16x (2)
We'll raise to square (1):
x^4 = 4y^2
We'll divide by 4 both sides:
y^2 = x^4/4 (3)
We'll substitute (3) in (2):
x^4/4 = 16x
We'll cross multiply and we'll get:
x^4 = 4*16x
We'll subtract 64 both sides:
x^4 - 64x = 0
We'll factorize by x:
x(x^3 - 64) = 0
We'll cancel each factor:
x = 0 and x^3 - 64 = 0
We'll re-write the difference of cubes, applying the formula:
a^3 - b^3 = (a-b)(a^2 + ab + b^2)
Let a = x and b = 4
x^3 - 64 = (x-4)(x^2 + 4x + 16)
(x-4)(x^2 + 4x + 16) = 0
We'll cancel each factor =>x - 4 = 0 => x = 4
We notice that x^2 + 4x + 16 > 0 for any real value of x.
If x = 4, we'll get y => 4^2 = 2y => y = 16/2 => y = 8
Therefore, if x = 4 and y = 8, the consecutive terms of the geometric series, whose common ratio is r =2, are: 2 , 4 , 8 , 16, ....
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