A gas sample in a sealed vial orginally at 0.6 atm and 300 K,was heated to 450 K.What other property of the gas has changed?what is the value of this property after heating?

Expert Answers
jerichorayel eNotes educator| Certified Educator

When you heat a gas at constant volume, the gas molecules will be more excited due to the increased kinetic energy. Consequently, the pressure of the gas will increase. The property of the gas that will change is its pressure. This is commonly called as the Gay-Lussac's Law. 

P1/T1 = P2/T2

P1 = 0.6

P2 = ?

T1 = 300 K

T2 = 450 K

In this problem we are looking for the pressure of the gass when the temperature is increased to 450K.

0.6/300 = P2/450

P2 = 0.9 atm

After heating, the pressure has increased.