Gas is contained in a tank at a pressure of 10 atm and a temperature of 15C. If one half of the gas is withdrawn and the temperature is raised to 65C, what is the new pressure in the tank? 

Expert Answers
jeew-m eNotes educator| Certified Educator

Here we have to understand the situation.

Here the mass of the gas is changing or amount of moles in the gas is changing. Since we have a tank to retain gas the volume of gas will remain constant.

Using `PV = nRT`

 

For first case

`P = 10`

`V = V`

`n = n1`

`T = 273+15 = 288`

 

`10xxV = n1xxRxx288---(1)`

 

In the second case the mass of the gas is halved. That means the amount of moles is also halved.

 

For second case

`P = ?`

`V = V`

`n = (n1)/2`

`T = 273+65 = 338`

 

` PV = (n1)/2xxRxx338 ---(2)`

 

 

`(2)/(1)`

`P/10 = ((1/2)xx338)/(288)`

`P = 5.87 atm`

 

So the final pressure of the gas is 5.87atm

 

Assumption

Gas act as an ideal gas