`g(x) = x^2 - 9, (2, -5)` Find the slope of the tangent line to the graph of the function at the given point.
hkj1385 | Certified Educator
The given function is:-
g(x) = (x^2) - 9
differentiating both sides w.r.t 'x' we get
g'(x) = 2x - 0
Now, slope of the tangent at the point (2,-5) = g'(2) = 2*2 = 4