`g(x) = x^2 - 9, (2, -5)` Find the slope of the tangent line to the graph of the function at the given point.

Textbook Question

Chapter 2, 2.1 - Problem 7 - Calculus of a Single Variable (10th Edition, Ron Larson).
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hkj1385 | (Level 1) Assistant Educator

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The given function is:-

g(x) = (x^2) - 9

differentiating both sides w.r.t 'x' we get

g'(x) = 2x - 0

Now, slope of the tangent at the point (2,-5) = g'(2) = 2*2 = 4

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