`g(x) = sqrt(x) e^x` Differentiate.

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Chapter 3, 3.2 - Problem 4 - Calculus: Early Transcendentals (7th Edition, James Stewart).
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balajia | College Teacher | (Level 1) eNoter

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`g(x)=x^(1/2)e^x`

`g'(x)=(1/2)x^(1/2 - 1)e^x+x^(1/2)e^x`

`=1/(2sqrt(x))e^x+sqrt(x)e^x`

`=(1/(2sqrt(x))+sqrt(x))e^x`

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