`g(x) = log_a (x), x = a^2` Evaluate the function at the indicated value of `x` without using a calculator.

Textbook Question

Chapter 3, 3.2 - Problem 19 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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Plug in the value of x in `g(x)`

`g(x)=log_a(a^2)`

`=2log_a(a)`

Note that `log_a(a)= `

Therefore,

`g(x)=2 `

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