`g(x) = log_b (x), x = b^-3` Evaluate the function at the indicated value of `x` without using a calculator.

Textbook Question

Chapter 3, 3.2 - Problem 20 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

Posted on

Plug in the value of x in

`g(x)=log_b(b^-3)`

Bring down the exponent

`=-3lob_b(b)`

Note that `log_b(b)=1 `

Therefore,

`g(x)=-3 `

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