`g(x) = 5000(2^x), x = -1.5` Evaluate the function at the indicated value of x. Round your result to three decimal places.

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Chapter 3, 3.1 - Problem 11 - Precalculus (3rd Edition, Ron Larson).
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loves2learn | (Level 3) Salutatorian

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Plug in the value `x=-1.5 ` in for the function `g(x) `

`g(x)=5000(2^(-1.5)) `


`g(x)=1767.767 `

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