`g(x) = (3/2)x + 1, (-2, -2)` Find the slope of the tangent line to the graph of the function at the given point.

Expert Answers
hkj1385 eNotes educator| Certified Educator

The given function is:-

g(x) = (3/2)x + 1

differentiating both sides w.r.t 'x' we get

g'(x) = (3/2) + 0

Now, slope of the tangent at the point (-2,-2) = g'(-2) = 3/2