`g(x) = (3/2)x + 1, (-2, -2)` Find the slope of the tangent line to the graph of the function at the given point.
hkj1385 | Certified Educator
The given function is:-
g(x) = (3/2)x + 1
differentiating both sides w.r.t 'x' we get
g'(x) = (3/2) + 0
Now, slope of the tangent at the point (-2,-2) = g'(-2) = 3/2