`g(x) = (3/2)x + 1, (-2, -2)` Find the slope of the tangent line to the graph of the function at the given point.

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Chapter 2, 2.1 - Problem 6 - Calculus of a Single Variable (10th Edition, Ron Larson).
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hkj1385 | (Level 1) Assistant Educator

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The given function is:-

g(x) = (3/2)x + 1

differentiating both sides w.r.t 'x' we get

g'(x) = (3/2) + 0

Now, slope of the tangent at the point (-2,-2) = g'(-2) = 3/2

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