`g(x) = 2x^2 - 8x, [0,6]` Find the absolute extrema of the function on the closed interval.

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Given: `g(x)=2x^2-8x,[0,6]`

First find the critical x value(s) of the function. You will do this by setting the derivative function equal to zero and solving for the x value(s).




Plug in the critical x value(s) and the endpoints of the closed interval into the g(x) function.





Examine the g(x) values.

The absolute maximum value will be the point (6, 24).

The absolute minimum value will be the point  (2, -8).

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