`g(x) = 2x^2 - 3x, c=2` Use the alternative form of the derivative to find the derivative at x = c (if it exists).

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Chapter 2, Review - Problem 5 - Calculus of a Single Variable (10th Edition, Ron Larson).
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nees101 | Student, Graduate | (Level 2) Adjunct Educator

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Given the function `f(x)=2x^2-3x` , c=2.

We have to use the alternative form of derivative to find the derivative at x=c.

Here given that c=2.

So by definition of alternative derivative we have,



` =lim_(x->2)(2x^2-3x-(2(2^2)-3(2)))/(x-2)`



`=lim_(x->2) 2x+1`


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