Given: `g(v)=cos(v)/csc(v)`

The original function equivalent to `g(v)=cos(v)sin(v).`

`g'(x)=cos(v)cos(v)+sin(v)(-sin(v))`

`g'(x)=cos^2(v)-sin^2(v)`

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Given: `g(v)=cos(v)/csc(v)`

The original function equivalent to `g(v)=cos(v)sin(v).`

`g'(x)=cos(v)cos(v)+sin(v)(-sin(v))`

`g'(x)=cos^2(v)-sin^2(v)`

``