`g(t) = 5(cos(pit))^2` Find the derivative of the function.

Textbook Question

Chapter 2, 2.4 - Problem 54 - Calculus of a Single Variable (10th Edition, Ron Larson).
See all solutions for this textbook.

1 Answer | Add Yours

hkj1385's profile pic

hkj1385 | (Level 1) Assistant Educator

Posted on

g(t) = `5(cos(pit))^2`

`g'(t) = 5*2*cos(pit)*{-sin(pit)}*pi`

`or, g'(t) = -10cos(pit)*sin(pit)`

`or, g'(t) = -5sin(2pit)`

Note:-

1)`2sint*cost = sin2t`

``

We’ve answered 318,995 questions. We can answer yours, too.

Ask a question