`g(r) = int_0^r(sqrt(x^2 + 4))dx` Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.

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Chapter 5, 5.3 - Problem 10 - Calculus: Early Transcendentals (7th Edition, James Stewart).
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Borys Shumyatskiy | College Teacher | (Level 3) Associate Educator

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Hello!

Part 1 of the Fundamental Theorem of Calculus states that for a continuous function `f`
`F'_a(x)=f(x),` where `F_a(x)=int_a^xf(t)dt.`

 

Here `f(t)=sqrt(t^2+4)` and `g(x)=F_0(x).`

 

Therefore

`g'(x)=F'_0(x)=f(x)=sqrt(x^2+4).`

or `g'(r)=sqrt(r^2+4)`  (identical variable replacement).

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