For the function y=(x-5)(x+2) please explain the following questions.
For the function y=(x-5)(x+2)
A.What are the x-intercepts?
B.What is the axis of symmetry?
C.What are the coordinates of the vertex?
D.Graph the function.
The function y=(x-5)(x+2) is that of a parabola.
=> y = x^2 - 3x - 10
=> y = (x - 3/2)^2 - 49/4
The x-intercepts of the graph are the solution of the equation (x - 5)(x + 2) = 0 which gives x = 5 and x = -2.
The axis of symmetry is: x = 3/2
The vertex is (3/2, -49/4)
The graph of the function is given below with the axis shown in red.